Question 696959
{{{log(6,(x^2+7))=log(6,(1-5x))}}}...this will be equal for


{{{x^2+7=1-5x}}}...now find solutions for {{{x}}}


{{{x^2+5x+7-1=0}}}


{{{x^2+5x+6=0}}}.....use quadratic formula


 {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}...enter {{{a=1}}}, {{{b=5}}}, and {{{c=6 }}}


 {{{x = (-5 +- sqrt( 5^2-4*1*6 ))/(2*1) }}}


{{{x = (-5 +- sqrt( 25-24 ))/2 }}}


{{{x = (-5 +- sqrt( 1 ))/2 }}}


{{{x = (-5 +- 1)/2 }}}


solutions:

{{{x = (-5 + 1)/2 }}}

{{{x = -4/2 }}}

{{{highlight(x = -2) }}}

or

{{{x = (-5 - 1)/2 }}}

{{{x = -6/2 }}}

{{{highlight(x = -3) }}}