<PRE><B>Question 62233</B>
(1/3)log&lt;sub&gt;2&lt;/sub&gt;(x+6) = log&lt;sub&gt;8&lt;/sub&gt;3x

=&gt; (1/3)log&lt;sub&gt;2&lt;/sub&gt;(x+6) = (log&lt;sub&gt;2&lt;/sub&gt;3x)/(log&lt;sub&gt;2&lt;/sub&gt;8)
=&gt; (1/3)log&lt;sub&gt;2&lt;/sub&gt;(x+6) = (log&lt;sub&gt;2&lt;/sub&gt;3x)/3*(log&lt;sub&gt;2&lt;/sub&gt;2)
=&gt; (1/3)log&lt;sub&gt;2&lt;/sub&gt;(x+6) = (1/3)(log&lt;sub&gt;2&lt;/sub&gt;3x)
=&gt; log&lt;sub&gt;2&lt;/sub&gt;(x+6) = (log&lt;sub&gt;2&lt;/sub&gt;3x)
Taking antilog on both sides
=&gt; (x+6) = 3x
=&gt; 2x = 6
=&gt; x = 3





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