<PRE><B>Question 696910</B>
Find three consecutive even integers such that when the first integer is multiplied by the third integer, the result is 2 more than 5 times the second integer. 
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1st: 2x-2
2nd: 2x
3rd: 2x+2
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Equation:
(2x-2)(2x+2) = 5(2x)+2
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4x^2-4 = 10x + 2
4x^2 - 10x -6 = 0
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2x^2 -5x -3 = 0
(2x+1)(x-3) = 0
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Positive solution:
x = 3
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1st: 2x-2 = 4
2nd: 6
3rd: 8
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Cheers,
Stan H.
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