Question 696865
f(x)= x^2+2/x-1
f(3)=3^2+2/3-1
    =9+2/2
    =9+1
    =10
g (x) = 2/x
g(3)=2/3
(f-g) (3)=
(f-g)=(x^2+2/x-1)-(2/x)  
     =(x^3+2)/(x^2-x)
(f-g)(3)=(3^3+2)/(3^2-3)
        =29/6

 (fg)(3)=f(3)*g(3)
        =10*2/3
        =20/3
fog(3)=f *g[3] 
      =f(2/3)
       =(2/3)^2+2/(2/3 -1)
       =4/9+  (2/█(2/3-1))   
       =4/9+6/(-1)
       =-50/9