Question 696868
a(3)=4
s(8)=36
s(n)=(n/2)(2a+(n-1)d)
here n=8
therefore, s(8)=4(2a+7d)=8a+28d=36 - first equation
also a(n)=a+(n-1)d
therefore a(3)=a+2d=4 - second equation

now solve both equation

8(4-2d)+28d=36
32-16d+28d=36
32+12d=36
12d=4
d=1/3

therefore a=4-2d=4-2(1/3)=10/3

now using formula for terms i.e. a(n)=a+(n-1)d

10/3, 11/3, 4, 13/3, 14/3, 5 ,16/3 , 17/3


solved....cheers

my method is easier than mentioned above