Question 696868
The nth term of an arithmetic sequence is
{{{ a[n] = a[1] + (n-1)d }}} 

The third term is 4,therefore
{{{ a[3] = a[1] + (3-1)d }}} or
{{{ 4 = a[1] + 2d }}} 

The sum of the first n terms of an arithmetic sequence is
{{{ S[n] = (n/2)(a[1] + a[n])}}}

The sum of the first 8 term is 36,therefore
{{{ S[8] = (8/2)(a[1] + a[8])}}} or
{{{ 36 = 4(a[1] + a[8])}}} ,divide by 4
{{{ 9 = a[1] + a[8]}}}, substitute {{{ a[8] = a[1] + 7d}}}
{{{ 9 = a[1] +  a[1] + 7d }}}
{{{ 9 = 2a[1] + 7d }}}

Solve the system
{{{4 = a[1] + 2d}}}
{{{9 = 2a[1] + 7d}}}

Multiply the first equation by -2
{{{-8 = -2a[1] - 4d}}}
{{{9 = 2a[1] + 7d}}}

Add the two equations
1 = 3d
d = 1/3, substitute in the first equation and solve for {{{ a[1]}}}

{{{4 = a[1] + 2/3}}}
{{{a[1] = 10/3}}},add 1/3 to get the next terms

The first 8 terms are:
{{{10/3}}}, {{{11/3}}}, {{{ 4}}}, {{{13/3}}}, {{{14/3}}}, {{{5}}}, {{{16/3}}}, and  {{{17/3}}}