Question 696806

Could you please help me with the following?

Solve for x in {{{1-x-(2/(6x+1))=0}}}. My working is..

{{{2=(6x+1)(1-x)=6x^2+5x+1}}}
{{{6x^2+5x-1=0}}}
Into the quadratic formula...
{{{x=(-5+sqrt(5^2-(4*6*-1))/12) = (-5+7)/12}}}
{{{x=(-5+7)/12=1/6}}} or {{{x=(-5-7)/12=-1}}}

The correct answer is x=1/3, x=1/2?

Thanks.


{{{1 -x -(2/(6x + 1))=0}}}


** Note that {{{x <> - 1/6}}}


1(6x + 1) - x(6x + 1) - 2 = 0(6x + 1) ----- Multiplying by LCD, 6x + 1


{{{6x + 1 - 6x^2 - x - 2 = 0}}}


{{{- 6x^2 + 6x - x + 1 - 2 = 0}}}


{{{- 6x^2 + 5x - 1 = 0}}}


{{{0 = 6x^2 - 5x + 1}}}, or {{{6x^2 - 5x + 1 = 0}}}


You can now solve for x. Notice that the equation is different from yours!!


You can then do the check!!


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