<PRE><B>Question 696806</B>
{{{1-x-(2/(6x+1))=0}}}

Can be reduced to {6x^2 - 5x +1 }  = 0

6x^2 - 3x - 2x + 1 = 0

{3x ( 2x - 1 ) - 1(2x - 1 )} = 0

{{(2x - 1) (3x - 1) }  = 0}

{2x - 1 } = 0 OR {3x - 1 } = 0.

{ X = {(1/2) or (1/3)}}

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