Question 696670

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(1980,18000\right)]. So this means that {{{x[1]=1980}}} and {{{y[1]=18000}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(2000,42000\right)].  So this means that {{{x[2]=2000}}} and {{{y[2]=42000}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(42000-18000)/(2000-1980)}}} Plug in {{{y[2]=42000}}}, {{{y[1]=18000}}}, {{{x[2]=2000}}}, and {{{x[1]=1980}}}



{{{m=(24000)/(2000-1980)}}} Subtract {{{18000}}} from {{{42000}}} to get {{{24000}}}



{{{m=(24000)/(20)}}} Subtract {{{1980}}} from {{{2000}}} to get {{{20}}}



{{{m=1200}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(1980,18000\right)] and *[Tex \LARGE \left(2000,42000\right)] is {{{m=1200}}}