Question 696661
{{{sqrt(3x+1)+1=x}}}


{{{sqrt(3x+1)=x-1}}}


{{{3x+1=(x-1)^2}}}


{{{0=(x-1)^2-3x-1}}}


{{{(x-1)^2-3x-1=0}}}


{{{x^2-2x+1-3x-1=0}}}


{{{x^2-5x=0}}}


{{{x(x-5)=0}}}


{{{x=0}}} or {{{x-5=0}}}


{{{x=0}}} or {{{x=5}}}


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So the two *possible* answers are {{{x=0}}} or {{{x=5}}}


However, only one of these solutions actually work (ie are actually solutions). 


You have to check to see if they work (which is something I leave for you to do)