Question 696658

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-3,2\right)]. So this means that {{{x[1]=-3}}} and {{{y[1]=2}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-1,-4\right)].  So this means that {{{x[2]=-1}}} and {{{y[2]=-4}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-4-2)/(-1--3)}}} Plug in {{{y[2]=-4}}}, {{{y[1]=2}}}, {{{x[2]=-1}}}, and {{{x[1]=-3}}}



{{{m=(-6)/(-1--3)}}} Subtract {{{2}}} from {{{-4}}} to get {{{-6}}}



{{{m=(-6)/(2)}}} Subtract {{{-3}}} from {{{-1}}} to get {{{2}}}



{{{m=-3}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-3,2\right)] and *[Tex \LARGE \left(-1,-4\right)] is {{{m=-3}}}