Question 696632
A survey was conducted to measure the height of men. In the survey, respondents were grouped by age. In the 20-29 group the groups were normally distributed, with a mean of 68.4 inches and a standard deviation of 4 inches. A study participant is randomly selected. Complete parts a through c
a. Find the probability that his height is less than 66 inches
z(66) = (66-68.4)/4 = -0.6
P(x < 66) = P(z < -0.6) = normalcdf(-100,-0.6) = 0.2743
----------------------------------------------------------------
b. FInd the probability that the height is between 66 and 71 inches
z(71) = (71-68.4)/4 = 0.65
P(66< x <71) = P(-0.6< z <0.65) = normalcdf(-0.6,0.65) = 0.4675
------------------------------------
c. Find the probability that the height is more than 71 inches
P(x > 71) = P(z > 0.65) = normalcdf(0.65,100) = 0.2578
==========================
Cheers,
Stan H.