Question 62147
Joseph has 4 times as many quarters as he does dimes. If he has a total of $2.65, how many of each type of coin does he have?
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Let the number of dimes be "x"; Value of these is 10x cents
The number of quarters is "4x"; Value of these is 25(4x)=100x cents
EQUATION:
value + value = 265 cets
10x+100x=265
110x=265
x=2.4...
This is not possible as "x" is a count of coins.
Check your problem data and your posting.
Cheers,
Stan H.