Question 62098
2 trains left the same city at the same time, traveling in opposite directions. the eastbound train travels for 10 hours, and the westbound train travels for 5 hours. They are now 1300 km. apart. the westbound train's rate is 20 km/h faster than the eastbound train. Find the rate of the speed of each train.
:
Let s = speed of the slower train:
Then (s+20) = speed of the faster train
:
Dist = time * speed
:
Eastbound dist + westbound dist = 1300
10s + 5(s+20) = 1300
10s + 5s + 100 = 1300
15s = 1300 - 100
15s = 1200
s = 1200/15
s = 80 mph for slow one and 100 mph for the fast one
:
Check 80*10 + 100*5 = 1300
:
How about this? Did it make sense to you?