Question 696260
<font face="Times New Roman" size="+2">


If the vertex is (2,-12) and it passes through the origin, then symmetry says it must also pass through (4,0).


The general form of a parabola function is


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ ax^2\ +\ bx\ +\ c]


So, if *[tex \LARGE y\ =\ -12] when *[tex \LARGE x\ =\ 2], then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4a\ +\ 2b\ +\ c\ =\ -12]


and if *[tex \LARGE y\ =\ 0] when *[tex \LARGE x\ =\ 0], then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ c\ =\ 0]


and if *[tex \LARGE y\ =\ 0] when *[tex \LARGE x\ =\ 4], then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 16a\ +\ 4b\ +\ c\ =\ 0]


Solve the 3X3 linear system to get the coefficients a, b, and c.  Use them to write your equation by substituting into:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ ax^2\ +\ bx\ +\ c]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>