Question 62124
The intersection of the barn and silo is a secant line 
that cuts across the circular base and is 10' long.
Draw a perpendicular from center of silo to the center of the secant.
Problem says center to the secant is 5". It divides the secant into 
2 5' sections, forming 2 45-45-90 triangles. The area of the
base of the silo is therefore, 
{{{pi*(5)^2 - (pi*(5^2)/4 - (1/2)*(5sqrt(2))^2)}}}
{{{25pi - ((25/4)*pi - 50/2)}}}
{{{25(pi - pi/4 + 1)}}}
{{{25(3pi/4 + 1)}}}
capacity is height X area of base
{{{30*25*(3.3562)}}}
{{{1767}}} ft3
unless I made a mistake