Question 696232
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All sides of a rhombus are equal in measure, so AB is congruent to AD and BC is congruent to DC. Then BD is congruent to BD by reflexive equality.  Hence ABC is congruent to CDA by SSS.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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