Question 696050
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First use the point-slope form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the given slope.


Then solve your equation for *[tex \LARGE y], which is to say arrange it in the form *[tex \LARGE y\ =\ mx\ +\ b] also known as the slope-intercept form.  Then the *[tex \LARGE y]-intercept is the point *[tex \LARGE (0,b)] where *[tex \LARGE  b] is the constant term of the slope-intercept form.  Be sure you report the *[tex \LARGE y]-intercept as an ordered pair with a zero *[tex \LARGE x]-coordinate.  An intercept is a point that is only properly designated in *[tex \LARGE \mathbb{R}^2] with an ordered pair.  Expressing the *[tex \LARGE y]-intercept as a single number is an error.


There is an alternate process for determining the *[tex \LARGE y]-coordinate of the *[tex \LARGE y]-intercept.  Using whatever equation form you like, substitute 0 for *[tex \LARGE x].  Then do the arithmetic required to determine the resulting value of *[tex \LARGE y].  That value will be *[tex \LARGE b], the *[tex \LARGE y]-coordinate of the *[tex \LARGE y]-intercept.  You still have to report an ordered pair as your answer.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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