Question 695982
{{{ x^4-4x^2+3=0 }}}
{{{ (x^2-3)(x^2-1) =0 }}}


so either {{{ x^2-3 =0 }}} giving:
{{{ x^2=3 }}}
{{{ x = ""+- sqrt(3) }}}


or {{{ x^2-1 =0 }}} giving:
{{{ x^2=1 }}}
{{{ x = ""+- 1 }}}


Hence the solutions are:
{{{ x = ""+- 1 }}} and {{{ x = ""+- sqrt(3) }}}