Question 695882
Let the width of the rectangle be {{{ w }}}
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"The length of a rectangle is 5 feet more than the width":
so the dimensions of the rectangle are {{{ w }}} and {{{ w+5 }}}
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"The perimeter is 38 feet":
{{{ 2w + 2(w+5) = 38 }}}
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"Find the length and width of the rectangle":
{{{ 2w + 2w + 10 = 38 }}}
{{{ 4w = 28 }}}
{{{ w = 7 }}}
So the width is 7 and the length is 11