Question 695417
{{{(6x^5-19x^4+18x^3-17x^2+23x-5) / (3x-5)}}}
...
3x-5 goes into {{{6x^5-19x^4}}}: {{{2x^4}}}
to get
{{{6x^5-10x^4}}}
subtracting
{{{6x^5 - 6x^5 - 19x^4 - -10x^4}}}
yielding
{{{-9x^4}}}
...
3x-5 goes into {{{-9x^4 + 18x^3}}}: -3x^3
to get 
{{{-9x^4 + 15x^3}}}
subtracting
{{{-9x^4 - -9x^4 + 18x^3 - 15x^3}}}
yielding
{{{3x^3}}}
...
3x-5 goes into {{{3x^3-17x^2}}}: {{{x^2}}}
to get
{{{3x^3 - 5x^2}}}
subtracting
{{{3x^3 - 3x^3 - 17x^2 - -5x^2}}}
yielding
{{{-12x^2}}}
...
3x-5 goes into {{{-12x^2 + 23x}}}: -4x
to get
{{{-12x^2 + 20x}}}
subtracting
{{{-12x^2 - -12x^2 + 23x - 20x}}}
yielding
3x
...
3x-5 goes into 3x-5: 1
to get
3x - 5
subtracting
3x - 3x -5 - -5
yielding
0
...
{{{(6x^5-19x^4+18x^3-17x^2+23x-5)/(3x-5) = highlight_green(2x^4-3x^3+x^2-4x+1)}}}
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