Question 695373
y intercept = 2/3
so the interception point on y axis = (0,(2/3))

slope = -5

Using the slope point form of equation

y-y1=m(x-x1)

where (x1,y1) are the co ordinates and m is the slope

y-(2/3) = -5(x-0)

y-(2/3) =-5x

y= -5x+(2/3)  ( slope intercept form)

Multiply by 3

3y=2-15x
15x+3y=2 ( standard form)