Question 695312
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*[tex \LARGE D\ \ =\ \left|-1\ \ \ 5\cr\ \ 1\ -2\right|\ =\ (-1\,\cdot\,-2)\ -\ (1\,\cdot\,5)\ =\ -3]


*[tex \LARGE D_x\ =\ \left|\ \ 2\ \ \ 5\cr-2\ -2\right|\ =\ (2\,\cdot\,-2)\ -\ (-2\,\cdot\,5)\ =\ 6]


*[tex \LARGE D_y\ =\ \left|-1\ \ \ 2\cr\ \ 1\ -2\right|\ =\ (-1\,\cdot\,-2)\ -\ (1\,\cdot\,2)\ =\ 0]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{D_x}{D}\ =\ \frac{6}{-3}\ =\ -2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ \frac{D_y}{D}\ =\ \frac{0}{-3}\ =\ 0]
 

</pre>
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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