<PRE><B>Question 695266</B>
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If it is a right triangle, then the hypotenuse must be the longest side.  If *[tex \LARGE a] and *[tex \LARGE b] are the two shorter sides and the longest side is *[tex \LARGE c] and then if *[tex \LARGE c\ =\ \sqrt{a^2\ +\ b^2}] then the triangle is right.


So figure out which of 11, 5, and *[tex \LARGE \sqrt{146}] is the largest number, then calculate *[tex \LARGE a^2\ +\ b^2] where *[tex \LARGE a] and *[tex \LARGE b] are the two short sides.  If the result is 146, then the triangle is right, otherwise not.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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