Question 62091
<b>solve the equation 4^2x+1=2^3x+6</b>

You were very close but you calculated that 2*(2x+1) = 4*x+1 when it is in fact 4*x+2.

{{{4^(2x+1) = 2^(3x+6)}}}.
{{{2^(2^(2x+1)) = 2^(3x+6)}}}.
{{{2^(4x+2) = 2^(3x+6)}}}.
{{{4x+2 = 3x+6}}}.
{{{4x=3x+4}}}.
{{{x=4}}}.

Check your answer and you would have caught the mistake.

{{{4^(2(4)+1) = 4^9 = 2^18}}}.
{{{2^(3(4)+6) = 2^18}}}.