Question 694956
A set of normally distributed data has mean 47  and standard deviation 0.6 s. Find the percentage of the data within these intervals:
a. Between 46 and 47 
Draw a normal curve with mean = x = 47
Plot 46 on the x-axis
Find the z-value of 47
z(46) = (46-47)/0.6 = -1/0.6 = -5/3
Note: The z-value of the mean is 0
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Percentage between 46 and 47 = P(-5/3 < z < 0) = 0.4522
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b. Greater than 1.5s above or below the mean
If that "s" means standard deviation the answer is:
normalcdf(-100,-1.5) = 0.0668
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Cheers,
Stan H.
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