Question 694977
Three identical slips of paper with the numbers 1, 2,
and 3 (one number on each slip) are placed in a box.One
slip is randomly selected, and then,without
replacement, a second slip is selected. Find the
probability that the sum of the two numbers is even. 
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Total number of results: 3*2 = 6
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Even results: 1+3 = 4 ; 3+1 = 4 = 2 ways
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Ans: P(even sum) = 2/6 = 1/3
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Cheers,
Stan H.