Question 695025

how would you solve
log2^(x-2)+ log2(x-3)=1


{{{log (2, (x - 2)) + log (2, (x - 3)) = 1}}}


{{{log (2, (x - 2)(x - 3)) = 1}}}


{{{log (2, (x^2 - 5x + 6)) = 1}}}


{{{x^2 - 5x + 6 = 2^1}}}


{{{x^2 - 5x + 6 - 2 = 0}}}


{{{x^2 - 5x + 4 = 0}}}


(x - 1)(x - 4) = 0


x = 1 (ignore as the log of a number CANNOT be negative)


{{{highlight_green(x = 4)}}}


You can do the check!!


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