Question 694907
{{{ f(x) = sqrt(x-3) + 2 }}}

DOMAIN:
f(x) can take all values of x such that {{{ x-3 >= 0 }}} 
so the domain is {{{ x >= 3 }}}

RANGE:
{{{ sqrt(x-3) }}} has a minimum of 0 when x=3
so {{{ sqrt(x-3) + 2 }}} has a minimum of 2 when x=3
so the range is {{{ f(x)>=2 }}}, or {{{ 2<=f(x)<infinity }}}