Question 694868


{{{log (3 ,sqrt (3))}}}...in base {{{10}}} you will have


={{{log (sqrt (3))/log (3) }}}.........{{{log (sqrt (3))=log (3^(1/2))=(log(3))/(2 log(10))}}}


={{{(log(3))/(2 log(10))/log (3) }}}


={{{(cross(log(3)))/(2 log(10))/cross(log (3)) }}}


={{{1/(2 log(10)) }}}.......{{{2 log(10)=log(10^2)=2}}}


={{{1/2 }}}