<PRE><B>Question 694747</B>
a bus travel at 36 km per hour and arrive its destination half an hour late if the bus travel at 42 km per hour and it arrives at its destination half an hour earlier find the distance
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Slower Bus DATA:
rate = 36 km/hr ; distance = x km ; time = d/r = x/36 hrs
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Faster Bus DATA:
rate = 42 km/hr ; distance = x km ; time = d/r = x/42 hrs
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Equation:
slow time - fast time = (1/2) hr
x/36 - x/42 = 1/2
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(42x-36x)/(36*42) = 1/2
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6x = 18*42
x = 18*7
x = 126 km
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Cheers,
Stan H.
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