Question 694541
Area of triangle = (1/2) *base * altitude

let base be x m
altitude = (x+2) m

Area = (1/2) *x*(x+2)

40= (1/2) *x^2+2x
80=x^2+2x

x^2+2x-80=0

x^2+10x-8x-80=0

x(x+10)-8(x+10)=0
(x+10)(x-8)=0
x=-10, OR 8

length cannot be negative
so base = 8m
Altitude = 8+2 = 10 m