Question 694602
<pre>
{{{(y-1)^2/4}}}{{{""-""}}}{{{(x-2)^2/16}}} = 1

It's in the form

{{{(y-k)^2/a^2}}}{{{""-""}}}{{{(x-h)^2/b^2}}} = 1

The center is (h,k) = (2,1)

Because the term in y comes first, it's a hyperbola like this {{{drawing(20,25,8,12,8.2,12.2, graph(20,25,8,12,8.2,12.2,sqrt(1+(x-10)^2)+10),

graph(20,25,8,12,8.2,12.2,-sqrt(1+(x-10)^2)+10) )}}}.

Therefore the vertices are "a" units above and below the center.

So they are (2,1±2), that is, (2,-1) and (2,3) 

Edwin</pre>