Question 694550
Perpendicular lines have negative inverse/reciprocal slopes.
Take a slope of 2, the negative inverse will be {{{-1/2}}}
A simple answer for two lines are
{{{highlight_green(y = 2)}}} and {{{highlight_green(x =-1/2)}}}, such that the first equation is a horizontal line through y=2 and the second equation is a vertical line through x = {{{-1/2}}}
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Given the points (2,-1) and (4,8), the slope is {{{(-1-8)/(2-4) = -9/-2 = 9/2}}}
With the points (1, 3) and (6, 2), the slope is {{{(3-2)/(1-6) = 1/-5 = -1/5}}}
No, these streets are not perpendicular, becuase their slopes are not negative inverses.
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