Question 1393
2q^2+14q = 2q-q^2-9
First we should put all the numbers on one side
2q^2+q^2-2q+14q+9 = 0
3q^2+12q+9 = 0
Now we can use the quadratic formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a)}}}
{{{x = (-12+-sqrt(12^2-4(3)(9)))/(2(3))}}}
{{{x = (-12+-sqrt(36))/6}}}
{{{x = (-12+-6)/6}}}
x = -6/6 or -18/6
x = -1 or -3