Question 694516
The 1st term is {{{ 1/2 }}}, so when 
{{{ n = 1 }}} ( 1st term ) , then you have
{{{ 1 / ( n + 1 ) }}}  when {{{ n = 1 }}} the term is {{{ 1/2 }}}
{{{ 1 / ( n + 1 ) }}} when {{{ n = 2 }}}  the term is {{{ 1/3 }}}
{{{ 1/ ( n + 1 ) }}} when {{{ n = 3 }}}  the term is {{{ 1/4 }}}
{{{ 1 / ( n + 1 ) }}} when {{{ n = 4 }}}  the term is {{{ 1/5 }}}
-----------------------------------
So you can see that whatever you choose for {{{ n }}},
the nth term will be {{{ 1 / ( n + 1 ) }}}
--------------------------------
Suppose I say {{{ n = 399 }}}, then the 399th term
will be {{{ 1 / ( 399 + 1 ) = 1 / 400 }}}
--------------------------------
Suppose the problem had been to find the nth term
of 1/2, 1/4, 1/6, 1/8, etc
The 1st term is also {{{ 1 / ( n + 1 ) }}}, but the
2nd term is {{{ 1 / ( n + 2 ) }}}, and the
3rd term is {{{ 1 / ( n + 4 ) }}}, etc
So, it keeps changing, and I still can't answer what 
the nth term will be.
------------------ 
What if I say that the nth term is 
{{{ 1/(2n) }}} when {{{ n = 1 }}}, the term is {{{ 1/2 }}} 
{{{ 1/(2n) }}} when {{{ n = 2 }}}, the term is {{{ 1/4 }}}
{{{ 1/(2n) }}} when {{{ n = 3 }}}, the term is {{{ 1/6 }}}
etc. ,so I can say that the nth term of 1/2, 1/4, 1/6, 1/8, etc
is {{{ 1/(2n) }}}
-----------------
It's a little tricky coming up with the expression that 
is general for all the terms, but this is the idea.
Hope it helps