Question 694423
Graph the quadratic function f(x)=5-x^2 and identify the Vertex. Give the Domain and Range
This is an equation of a parabola that opens downwards. (negative lead coefficient)
Its standard form: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex.
For given equation: y=-x^2+5 (rewritten)
vertex(0,5)
domain: (-∞,∞)
range: (-∞,5]
see graph below:
{{{ graph( 300, 300, -10, 10, -10, 10,-x^2+5) }}}