Question 694290



make a sketch of its cross section and draw in the height
I see a right -angled triangle with height h, so that

{{{l^2=h^2+(R-r)^2}}}...where {{{R}}} and {{{r}}} are {{{radii}}} of the base, {{{h}}} is {{{height}}}, and {{{l}}} is {{{slant_height}}}


given:

{{{l=5cm}}} 

the difference between radius of its two circular ends is {{{(R-r)= 4cm}}} 

{{{l^2=h^2+(R-r)^2}}}....plug in given values

{{{5^2=h^2+4^2}}}

{{{25 =h^2 + 16}}}

{{{h^2 = 25-16}}}

{{{h^2 = 9}}}

{{{highlight(h = 3cm)}}}

as you can see, the infamous {{{3-4-5}}} right-angled triangle