Question 694174
Hint: 


x^12=1


x^12 - 1 = 0


(x^4)^3 - 1^3 = 0


(x^4 - 1)((x^4)^2 + x^4*1 + 1^2) = 0


(x^4 - 1)(x^8 + x^4 + 1) = 0


(x^2 - 1)(x^2 + 1)(x^8 + x^4 + 1) = 0


(x - 1)(x + 1)(x^2 + 1)(x^8 + x^4 + 1) = 0


Note: 


To solve x^8 + x^4 + 1 = 0, let z = x^4 to get z^2 + z + 1 = 0. Solve for z and use this to find solutions to x.