Question 693844
Putting {{{ 5x -7y=3 }}} into standards form gives
{{{ 7y=5x-3 }}}
{{{ y=(5/7)x-3/7 }}}

so the line has gradient {{{ 5/7 }}}

The equation of a line with gradient {{{ m }}} passing through {{{ x[1],y[1] }}} satisfies the equation
{{{ y-y[1]=m(x-x[1]) }}}
So a line passing through the point (2,5) with gradient  {{{ 5/7 }}} satisfies the equation:
{{{ y-5=(5/7)(x-2) }}}
{{{ 7y-35=(5)(x-2) }}}
{{{ 7y-35=5x-10 }}}
{{{ 7y-35=5x-10 }}}
{{{ 7y-5x-25=0 }}}