Question 693738
log (b, A)}}}=3 and {{{log (b, B)}}}= (-2). 
Find {{{log (b, cube root AB)}}}).
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logb(A) = 3
logb(B) = -2
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Then logb(AB)^(1/3) = (1/3)[logb(A)+logb(B)
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= (1/3)logb(A) + (1/3)logb(B)
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= (1/3)3 + (1/3)(-2)
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= 1 - 2/3
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= 1/3
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cheers,
Stan H.
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