Question 7768
{{{((6x - 18)/(2x^2 - 5x - 3))*((4x^2 + 4x + 1)/(6x + 3))}}} Factor the numerators and the denominators:

{{{(6(x - 3)/(2x+1)(x-3))*(((2x+1)(2x+1))/3(2x+1))}}} Now cancel like factors in the numerators and the denominators. Cancel (x-3) once and (2x+1) two times.
This leaves you with: {{{6/3 = 2}}}