Question 62016
P(x)=x^4-4x^3-4x^2-4x-5 it aks me to find all rational zeros 
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x=-1 is one of the rational zeroes.
Dividing P(x) by x+1 you get a quotient 
of x^3-5x^2+x-5.
This cubic has a rational zero of x=5
Dividing it by x-5 you get a quotient 
of x^2+1 which has complex zeroes.
So the rational zeroes are x=1, x=5.
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Comment: Rational numbers are any number
which can be written as the ratio of two
integers.  Irrational zeroes cannot be 
expressed in this way.  For example sqrt2
pi, cube root of 5: these are all irrational.Cheers,
Stan H.