Question 693005
{{{(1-2sin^2(x))^2+4sin^2(x)cos^2(x)}}}
The expression in the parentheses is one of the variations of cos(2x):
{{{cos^2(2x)+4sin^2(x)cos^2(x)}}}
The second term is the square of sin(2x):
{{{cos^2(2x)+(2sin(x)cos(x))^2}}}
{{{cos^2(2x)+sin^2(2x)}}}
which equals
1