Question 693278
solve the following equation log[9](5x-3)- log[3]2√x = 0
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log9(5x-3) - [log9[2sqrt(x)]]/log9(3) = 0
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log9(5x-3) - [log9(2sqrt(x)]/(1/2) = 0
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log9(5x-3) - log9(4x) = 0
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log[(5x-3)/4x = 0
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(5x-3)/4x = 1
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5x-3 = 4x
x = 3
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Cheers,
Stan H.
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