Question 692372
With a 26-letter alphabet, there are {{{26}}} different choices for the first letter.
Each first letter choice leaves you {{{25}}} other letters that can be chosen as second letter.
So there are {{{26*25}}} ways to choose the first two letters,
and for each of those choices there are still {{{24}}} other letters to choose the third letter from.
So there are {{{26*25*24}}} ways to choose the first three letters,
and for each of those choices there are still {{{23}}} other letters to choose the fourth letter from.
So there are {{{26*25*24*23}}} ways to choose the four letters at the beginning of the license plate.
Then, there are 10 ways to choose each of the three digits, resulting in
{{{10*10*10=1000}}} combinations of three digits, from 000 to 999,
that can follow each of the {{{26*25*24*23}}} allowed four-letter combinations.
That gives us {{{26*25*24*23*1000=358800000}}} possible different license plates.
So the correct answer is a).