Question 693000

2*ln(x-3) = ln(x+5) + ln(4)


2*ln(x-3) = ln[(x+5)*4]


2*ln(x-3) = ln(4x+20)


ln[(x-3)^2] = ln(4x+20)


(x-3)^2 = 4x+20


x^2 - 6x + 9 = 4x+20


x^2 - 6x + 9 - 4x-20 = 0


x^2 - 10x - 11 = 0


(x-11)(x+1) = 0


I'll let you finish. Make sure to check both possible answers (since only one of these values is truly the answer)