Question 691658
find the vertex, focus, and the equation of the directrix of find the vertex, focus, and the equation of the directrix of (y-4)^2=8(x+3)
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I think you meant to write given equation as  (y-4)^2=8(x+3)
This is an equation of a parabola that opens rightwards:
Its standard form:((y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex, p=distance from the vertex to the focus and directrix on the axis of symmetry.
For given equation: (y-4)^2=8(x+3)
vertex: (-3,4)
axis of symmetry: y=4
4p=8
p=4
focus: (1,4)
directrix: x=-7