Question 61963
The given expression is: 


4a<sup>7</sup> + 48a<sup>6</sup> + 140a<sup>5</sup> 


Taking 4a<sup>5</sup> as a common factor, we get: 



4a<sup>5</sup> (a<sup>2</sup> + 12a + 35) 



This can be further written as: 


4a<sup>5</sup> [a(a + 12) + 35] 



Hence, the solution.