<PRE><B>Question 691774</B>
 solve for x
Assume the problem is:
a) {{{32^((x+4)) = 8^((3x-2))}}}
32 = 2^5, and 8 = 2^3, therefore we can write this
{{{2^(5(x+4)) = 2^(3(3x-2))}}}
if the base is equal the exponents are equal, write it:
5(x+4) = 3(3x-2)
5x + 20 = 9x - 6
20 + 6 = 9x - 5x
26 = 4x
x = 26/4
x = 6.5
:
:
Check this on your calc, enter both, compare the results
32^(6.5+4) 
and
8^(3(6.5)-2) 
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